awk - loop from a to z


 
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# 1  
Old 04-18-2011
Lightbulb awk - loop from a to z

Hello,

I was wondering if it is possible to do a loop on letters rather than numbers with awk (gawk).

Basically I used to do:
Code:
echo "nothing" | gawk '{for(i=1;i<11;i++)print i}'

But I would like to do something like that (which obviously does not work):
Code:
echo "nothing" | gawk '{for(i in a..z)print i}'

Any suggestion how to loop on the alphabet?

Thanks!

EDIT: At least I would need to be able to increment on the alphabet...
# 2  
Old 04-18-2011
I don't think plain awk has anything to turn an int into a char, but how about:
Code:
echo | awk 'BEGIN {  split("ABCDEFGHIJKLMNOPQRSTUVWXYZ", A, ""); }
{ for(N=1; N<=26; N++) printf("A[%d]=%d\n", N, A[N]); }'


Last edited by Corona688; 04-18-2011 at 02:44 PM..
# 3  
Old 04-18-2011
Quote:
Originally Posted by Corona688
I don't think plain awk has anything to turn an int into a char
You can use the %c format specifier. The following prints the lowercase alphabet (one letter per line):
Code:
awk 'BEGIN { for (i=97; i<123; i++) printf("%c\n", i) }'

Regards,
Alister
This User Gave Thanks to alister For This Post:
# 4  
Old 04-18-2011
Code:
 echo {a..z} |xargs -n1

This User Gave Thanks to yinyuemi For This Post:
# 5  
Old 04-18-2011
Code:
echo "nothing" | [g]awk '{gsub(""," ");for(i=1;i<=NF;i++) print $i}'

# 6  
Old 04-18-2011
Thanks!

All the solutions proposed work fine.
For my use, Alister's is the most convenient (compact and self-contained).
# 7  
Old 04-18-2011
Code:
for i in {a..z} ; do  echo $i; done

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