pattern matching question


 
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# 1  
Old 04-18-2011
pattern matching question

Hi guys,
I have a file in the following format:
Code:
 4222   323K     323L     D222
  494   8134     A023     A024
   49   812A     9871     9872
  492   A961     A962     A963
  491   0B77     0B78     0B79
  495   0B7A     0B7B     0B7C
 4949  WER9     444L     999O

I need to grep the line which has 49 from the begining of the file ONLY
I use the following "grep" statement, but it returnes more then I need:

Code:
NUM=49$ grep "^ *${NUM} *" myfile

Not sure why?
Thanks a lot for any help

Last edited by Franklin52; 04-18-2011 at 10:59 AM.. Reason: Please use code tags
# 2  
Old 04-18-2011
Quote:
I need to grep the line which has 49 from the begining of the file ONLY
Actually, there are lots of lines that matches your search criteria.
# 3  
Old 04-18-2011
-Yes, and I need the output to be the line which has 49 as the first colomn:
49 812A 9871 9872
# 4  
Old 04-18-2011
something like this,

Code:
awk ' $1 == 49 { print }' filename

Please use appropriate input field delimiters.
# 5  
Old 04-18-2011
Code:
grep -E "^( ){0,}${NUM}( ){1,}" myfile

# 6  
Old 04-18-2011
Thanks a lot
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