Shell Programming and Scripting

hi All,

i want to add the single digit front of the line in the report file and string compare with pattern file.

patter file: pattern1.txt

pattern num
like 4
love 3
john 2

report file: report.txt

i like very much
but john is good boy
i will love u

so after execute the script output is report.txt file like

4 i like very much
2 but john is good boy
3 i will love u

---------- Post updated at 08:18 PM ---------- Previous update was at 12:52 PM ----------

Please update anyone using by sed command...

What the output, if have two and more patterns found in one line?

Code:

i like john very much

And why it needs be sed command?

hi ,

Please check now. what i want na ...i have a one report file and pattern file.
i get the pattern from pattern file and compare to report file if matchine i get the line and place the equal digit to front of the line in the same report file.

patter file: pattern1.txt

pattern num
like 4
love 3
john 2

report file: report.txt

i like very much
but john is good boy
i will love u

output -> report.txt file like

4 i like very much
2 but john is good boy
3 i will love u

Your still don't answer my question:

What's the expect output, if have two and more patterns found in one line?

Code:

i like john very much

something like:

Code:

4 2 i like john very much
or 
4 i like john very much
or 
2 i like john very much

output similar like.....

4 i like john very much

Sorry for miscommunication....Thanks in advance

Code:

awk 'NR==FNR{a[$1]=$2;next}
{for(i=1;i<=NF;i++) if($i in a) print a[$i] FS $0}' pattern report
4 i like very much
2 but john is good boy
3 i will love u

really Thank you....can u explain the command.

another thing i need to update the output report file itself.