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Auditing script

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# 1  
Old 04-14-2011
Auditing script
I need a command line that will ls -l a directory and pick (grep?) all files that don't match a desired owner without losing track of the filename at any point. This way I can list later on "here are all the files with an incorrect owner". Thanks in advance
# 2  
Old 04-14-2011
Is this what you want:

Code:
ls -l | egrep -v 'user_name'

# 3  
Old 04-14-2011
The find command can do what you want, pretty sure.

Code:
$ find /path/to/dir/ '!' -user validuser
/path/to/dir/inside/filenotbelongingtovaliduser
...
$

This User Gave Thanks to Corona688 For This Post:
stevensw
# 4  
Old 04-14-2011
What if you have a filename with the same name as the desired owner but has a different owner?

It would be nice if grep would only scan the owners column and ignore the rest, how to do this?

---------- Post updated at 09:16 AM ---------- Previous update was at 09:14 AM ----------

Thanks Corona that may be exactly what I'm looking for.
# 5  
Old 04-14-2011
Quote:
Originally Posted by stevensw
What if you have a filename with the same name as the desired owner but has a different owner?
If I understand you:

Code:
USERNAME="qwerty"
# finds files named ${USERNAME} exactly.
# if you want to broaden it, you can use glob-like *, etc (inside the quotes!)
# Only matches if the username is NOT ${USERNAME}.
find /path -name "${USERNAME}" '!' -user "$USERNAME"

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