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Creating a date (without time) in perl

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# 1  
Old 04-14-2011
Creating a date (without time) in perl
I have a perl script that automatically runs on Mondays.
I need to have it create a variable for last Monday's date thru that Sunday's date.

example: 04-01-2011 thru 04-08-2011

Its reporting numbers for the previous week beginning with Monday and ending on Sunday. So i dont have to go in each week and manually enter the date range in before the script runs.
I no nothing about perl except that the script is in perl.
# 2  
Old 04-14-2011
I'm not sure how wise it is for you to modify a perl script if you literally know nothing about perl. But here is a way to generate those dates:
Code:
$
$ date
Thu Apr 14 17:30:28 EDT 2011
$ cat range
#! /usr/bin/perl -w

@d=localtime (time() - (60*60*24*7) );
printf "%02d-%02d-%4d\n", $d[4]+1,$d[3],$d[5]+1900;
@d=localtime (time() - (60*60*24) );
printf "%02d-%02d-%4d\n", $d[4]+1,$d[3],$d[5]+1900;

$ ./range
04-07-2011
04-13-2011
$

Now that I posted my script, the perl experts will come around and show how it's really done. Smilie
# 3  
Old 04-14-2011
and that will automatically change the range each week?
# 4  
Old 04-14-2011
Quote:
Originally Posted by bbraml
and that will automatically change the range each week?
Yep. time() - (60*60*24*7) That says take the current time and then back up 7 days.
# 5  
Old 04-14-2011
Of course, you must run script on the monday to get mon-sun of Previous week. If, for example, you dont run the program until 1am on Tue you will get dates for Tue(last week) to Mon(yesterday).

Slight change to always give MON thru SUN dates:
Code:
#!/usr/bin/perl
@d=localtime( time() );
@e=localtime(time() - (24*3600*$d[6]) ) ;
@s=localtime(time() - (24*3600*($d[6]+6)) ) ;
printf("%02d-%02d-%4d\n", $s[4]+1, $s[3], $s[5]+1900);
printf("%02d-%02d-%4d\n", $e[4]+1, $e[3], $e[5]+1900);

# 6  
Old 04-15-2011
thank you both. I can use either because they do exactly what I need.

You're awesome!

---------- Post updated at 03:52 PM ---------- Previous update was at 07:50 AM ----------

one more thing, how would I make that printf statement a variable?
That way I can just call the variable and not use that long string...
# 7  
Old 04-15-2011
Not sure I understand the request, but maybe....
Code:
$ cat range
#! /usr/bin/perl -w

@d=localtime (time() - (60*60*24*7) );
$start = sprintf "%02d-%02d-%4d\n", $d[4]+1,$d[3],$d[5]+1900;
@d=localtime (time() - (60*60*24) );
$end = sprintf "%02d-%02d-%4d\n", $d[4]+1,$d[3],$d[5]+1900;


print "start = ", $start;
print "end = ", $end;

$
$
$
$
$ ./range
start = 04-08-2011
end = 04-14-2011
$

This User Gave Thanks to Perderabo For This Post:
bbraml
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