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Aging file not use and touch

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# 1  
Old 04-13-2011
Aging file not use and touch
Hi all,

Need advice from expect, below is my scripts to find the file not use and touch in storage and other directory.

This scripts divide by:

1. 30 days
2. 90 days
3. 180 days
4. 1 years
5. 3 years
6. 5 years

Then count total size in GB from 6 each category.

Sample my scripts:
Code:
 
# 30 days
find /mnt/emage -type f -mtime -30 ! -mtime -0 -exec ls -la {} \; > 30days.txt
cat 30days.txt | awk '{ SUM += $5 } END { printf "30days,%.2f\n",SUM /1024^3 }' >> aging_temp.csv

Code:
 
# 90 days
find /mnt/emage -type f -mtime -90 ! -mtime -60 -exec ls -la {} \; > 90days.txt
cat 90days.txt | awk '{ SUM += $5 } END { printf "90days,%.2f\n",SUM /1024^3 }' >> aging_temp.csv

Code:
 
# 180 days
find /mnt/emage -type f -mtime -180 ! -mtime -150 -exec ls -la {} \; > 180days.txt
cat 180days.txt | awk '{ SUM += $5 } END { printf "180days,%.2f\n",SUM /1024^3 }' >> aging_temp.csv

Code:
 
# 1 Years
find /mnt/emage -type f -mtime -365 ! -mtime -335 -exec ls -la {} \; > 1years.txt
cat 1years.txt | awk '{ SUM += $5 } END { printf "1years,%.2f\n",SUM /1024^3 }' >> aging_temp.csv

Code:
 
# 3 Years
find /mnt/emage -type f -mtime -1095 ! -mtime -1005 -exec ls -la {} \; > 3years.txt
cat 3years.txt | awk '{ SUM += $5 } END { printf "3year,%.2f\n",SUM /1024^3 }' >> aging_temp.csv

Code:
 
# 5 years
find /mnt/emage -type f -mtime -1825 ! -mtime -1675 -exec ls -la {} \; > 5years.txt
cat 5yeras.txt | awk '{ SUM += $5 } END { printf "5year,%.2f\n",SUM /1024^3 }' >> aging_temp.csv

Code:
 
mv aging_temp.csv aging.csv

Thanks.
# 2  
Old 04-13-2011
What is your question?

Code:
find /mnt/emage -type f \( -mtime -1825  -a -mtime +1675 \) -exec ls -la {} \;

Your syntax may want to change to the above as well. This example is:
less than 1825 days and greater than 175 days, using POSIX-compliant syntax for find.
# 3  
Old 04-13-2011
Thanks Jim Mcnamara.

My question is just only need expert in this forum verify and comment my scripts. Maybe have better scripts other than this.

From your post:
Code:
find /mnt/emage -type f \( -mtime -1825  -a -mtime +1675 \) -exec ls -la {} \;

This scripts maybe I can put in as 5 years aging. I have question for +1675, how do you calculate and get this figure?. What I understand -1825 is equal to 5 years.

How about 30 days, 90days, 180days, 3years, 1years and 5 years already have it.

Thanks.
# 4  
Old 04-14-2011
Another way to do it would be to loop through all the files something like this:
Code:
for f in $(find /mnt/emage -type f); do
    # examine and classify $f
done

This command will give you the file's age in seconds: date -r "$f" +%s

This command does the same: stat -c%Y "$f"

The current time in seconds: date +%s

The file's size in bytes: stat -c%s "$f"

You might be able to make a nicer script with the individual pieces.
# 5  
Old 04-14-2011
Thanks KenJackson,

I'm not understand, so sorry. Can you explain me how to run this script? and guide me to this in detail?

Thanks again.
# 6  
Old 04-14-2011
I didn't have time to write the script.
I just mentioned the commands that would be used to do it a different way.
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