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Checking conditions with AWK

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# 8  
Old 04-08-2011
One shot :
Code:
to_day=$(date '+%a%b%e' | sed 's/ //g')
awk -v dat=$to_day '{A[$1]++;x=($3~dat)?"(GC)":"(DR)";print $2","$2 x >"file3"}END{for(i in A) print i,(A[i]%2?i FS "(ERR)":i) >"file2"}' file1

use nawk if on SunOS / Solaris

@ Panyam Smilie

Code:
to_day=$(date '+%a%b%0e')

Will give (on Linux)
Code:
FriApr08

Whereas in the file the format is
Code:
FriApr8

By the way, this '0' option is not standard ...unknown on my solaris for example(see below) (... but ok it works on Linux ).
Code:
# date '+%a%b%0e'
FriApr%0e
# date '+%a%b%e'
FriApr 8

Last edited by ctsgnb; 04-08-2011 at 02:27 PM..
# 9  
Old 04-08-2011
Thanks for the quick response Guys !
# 10  
Old 04-08-2011
Thanks ctsgnb. How ever, I got a different result in my system ( might be OS dependent)!!!!

Code:
 
date '+%a%b%0e'
FriApr8
uname -a
HP-UX avalon B.11.11 U 9000/800 3547052374 unlimited-user license

# 11  
Old 04-08-2011
have another quick one ....

If i have a file with lines like this
Code:
 
 
2917    0DDD   RDF1+TDEV       75(5)   2917_3RAID5     33      05F:0_10F:0     10000000c961408f    0A9B   0AA1


and a reference file like this ...

Code:
 
0A9B,0A9B(DR)
0AA1,0AA1(GC)
0DDD,0DDD(ERR)

I want to replace column 2 ,9 and 10 with column 2 value of reference file if it matches to column 1 of reference file . If there is no match ..keep the same value

Output
Code:
 
2917    0DDD(ERR)   RDF1+TDEV       75(5)   2917_3RAID5     33      05F:0_10F:0 10000000c961408f    0A9B(DR)   0AA1(GC)

thx
# 12  
Old 04-09-2011
Code:
awk 'NR==FNR{$1=$1;A[$1]=$2}NR!=FNR{FS="  *";for(i=2;i<=NF;i++) {$i=(A[$i])?A[$i]:$i""};print}' FS=, referencefile FS=" " inputfile

# 13  
Old 04-09-2011
Thanks a lot ...
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