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reading comma separated data and reorder

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# 1  
Old 04-07-2011
reading comma separated data and reorder
hey guys!
i need to read data from a file that are comma separated then reorder them in another file to be generated

for example:

x,y,z
a,b,c
l,m,n
o,p,q

and transform this into:

x,a,l,o
y,b,m,p
z,c,n,q

Will appreciate your fast reply
Regards!
# 2  
Old 04-07-2011
Code:
 
awk -F"," 'NR==1{for(i=1;i<=NF;i++)a[i]=$i;next} {for(i=1;i<=NF;i++) a[i]=a[i]OFS$i} END{for(i=1;i in a;i++) print a[i]}' OFS=","  input_file

check it out on how to get the output in the same order you read it.
Last edited by panyam; 04-07-2011 at 12:52 PM.. Reason: changed the for loop a bit to get the data in order
# 3  
Old 04-07-2011
Try:
Code:
perl -F, -alne 'for ($i=0;$i<=$#F;$i++){push @{$h{$i}},$F[$i]}END{for ($i=0;$i<=$#F;$i++){$,=",";print @{$h{$i}}}}' file

# 4  
Old 04-07-2011
Ruby(1.9.1+)

Code:
$ ruby  -ne 'BEGIN{a=[]};a<<$_.chomp.split(",");END{a.transpose.each{|x| puts x.join(",") }}' file
x,a,l,o
y,b,m,p
z,c,n,q

# 5  
Old 04-10-2011
Quote:
Originally Posted by kurumi
Ruby(1.9.1+)

Code:
$ ruby  -ne 'BEGIN{a=[]};a<<$_.chomp.split(",");END{a.transpose.each{|x| puts x.join(",") }}' file
x,a,l,o
y,b,m,p
z,c,n,q

is this a language other that shell scripting? am sorry am a beginner
# 6  
Old 04-10-2011
Code:
i=1; while true ; do a=`cut -d, -f$i file` ; ((i++)); [ "$a" ] || break ; echo $a | tr ' ' ',' ; done

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