Shell Programming and Scripting

hyper link- abc:8081/xyz/2.5.6/rtyp-2.5.6.jar

Needs to get "rtyp-2.5.6.jar" i.e character after last backslash "/"
how to do this using sed/awk??

help is highly appreciated.

Code:

echo 'hyper link- abc:8081/xyz/2.5.6/rtyp-2.5.6.jar' | awk -F/ '{print $NF}'

thanks pravin u the master .
this site is excellent .hope i learn well from here.
once again thanks a ton

thanks pravin for quick & perfect reply. you genious.
hope i learn well more from this site.
once again hats off from a unix beginner

---------- Post updated at 02:42 PM ---------- Previous update was at 02:40 PM ----------

btw: can we do this similar thing using sed?? will help me in directly replacing in the file.

sed

Code:

echo 'hyper link- abc:8081/xyz/2.5.6/rtyp-2.5.6.jar' |sed 's:.*/::g'

OR

Code:

p='hyper link- abc:8081/xyz/2.5.6/rtyp-2.5.6.jar'
echo ${p##*/}

Using split method (Ruby1.9+)

Code:

$ echo "abc:8081/xyz/2.5.6/rtyp-2.5.6.jar" | ruby -e 'puts gets.split("/")[-1]'
rtyp-2.5.6.jar

Using regex

Code:

$ echo "abc:8081/xyz/2.5.6/rtyp-2.5.6.jar" | ruby -e 'puts gets.gsub(/.*\//,"")'
rtyp-2.5.6.jar

wow! ruby also looks good.
one issue facing is i have to do this in a file.
whose content is like
file.txt>>

anb/xrg/zxczxc.java
admin/WEB-INF/struts-config.xml
h-t-t-p://abc:8081/xyz/2.5.6/rtyp-2.5.6.jar

**h-t-t-p stands for hyperlink .not allowed to post them as of now

i need to cut only "http" lines with the jar names.
here its cutting all the lines & printing the last string after backslash.