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how to store output into variable-in unix shell scripting

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# 1  
Old 04-06-2011
how to store output into variable-in unix shell scripting
Hi,

Output of "ps -o etime,time,pcpu,pmem,fname -C sbd-java"
command is -
Elapsed Time %cpu %MEM COMMAND
02:14:03 00:03:28 2.5 6.3 sbd-java

Can anyone tell me, how to store the the value 2.5 in a variable?
When I say echo $X where x is a variable then output should be 2.5 only
Last edited by pspriyanka; 04-06-2011 at 08:56 AM.. Reason: space given in table
# 2  
Old 04-06-2011
Quote:
Originally Posted by pspriyanka
Can anyone tell me, how to store the the value 2.5 in a variable?
Read this thread, you will just have to filter out what interests you.

I hope this helps.

bakunin
# 3  
Old 04-06-2011
Thanks for helping me :-)
it's working using the following command-


X=`ps -o etime,time,pcpu,pmem,fname -C sbd-java --no-heading|awk '{print $3 }'`;

echo $X

output-2.5
# 4  
Old 04-06-2011
Quote:
Originally Posted by pspriyanka
[code]X=`ps -o etime,time,pcpu,pmem,fname -C sbd-java --no-heading|awk '{print $3 }'`[code]
You shouldn't use backticks at all! They are outdated and only supported by the shell for compatibility reasons. What's more, they can't be nested. Use "$(...)" instead of "`...`".

I hope this helps.

bakunin
# 5  
Old 04-07-2011
X=`ps -o etime,time,pcpu,pmem,fname -C sbd-java --no-heading|awk '{print $3 }'`;

echo $X

output-2.5

(This is the code for shell script working properly, i want use same application in perl script.
Is their any change required in above code.i have tried usind the same code in perl but its not working...)

can you plz tell me what changes need to be do??
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