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escaping path

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# 1  
Old 04-04-2011
escaping path
Hi
I use :
Code:
path=/var/www/admin
echo "$path" | sed -e 's/\//\\\//g'

this return
Code:
\/var\/www\/admin

and is ok.

but
Code:
path2=`echo "$path" | sed -e 's/\//\\\//g'`
echo $path2

return an error:
Code:
sed: -e expression #1, char 9: unknown option to `s'

Can anyone help me?
Thanks
Last edited by Franklin52; 04-04-2011 at 07:21 AM.. Reason: Please use code tags
# 2  
Old 04-04-2011
Code:
path2=$(echo "$path" | sed -e 's/\//\\\//g')

This User Gave Thanks to kato For This Post:
georgian
# 3  
Old 04-04-2011
Thank you very much.
It's perfect.
# 4  
Old 04-04-2011
You could save some backslash ( and avoid escaping the slash) by choosing another delimiter :

for example :
Code:
# echo "$PWD" | sed 's:/:\\/:g'

or
Code:
# echo "$PWD" | sed 's;/;\\/;g'

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