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Shell Script Incremental

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# 1  
Old 04-01-2011
Shell Script Incremental
I have a master sequence say

>Seq
ATGCGTA.......

That I want to repeat N no of times and each time the sequence is the same but the header changes in incremental numerical order

E.g.
>Seq1
ATGCGTA.......
>Seq2
ATGCGTA.......
>Seq3
ATGCGTA.......
.
.
.
.
>SeqN
ATGCGTA.......


Ultimately the user decides on the value of N

Does anyone know a quick way of doing this
# 2  
Old 04-01-2011
Code:
awk -v N=100 -v seq="ATGCGTA..." 'BEGIN{while(++i <= N)print "Seq" i RS seq}'

# 3  
Old 04-01-2011
Code:
$ num=10 #user input
$ ruby -e 'BEGIN{c=1;s=File.open("file").read};1.upto('$num'){|x| print s.gsub(/^>Seq/,">Seq#{c}");c+=1 }'
>Seq1
ATGCGTA.......
>Seq2
ATGCGTA.......
>Seq3
ATGCGTA.......
>Seq4
ATGCGTA.......
>Seq5
ATGCGTA.......
>Seq6
ATGCGTA.......
>Seq7
ATGCGTA.......
>Seq8
ATGCGTA.......
>Seq9
ATGCGTA.......
>Seq10
ATGCGTA.......

# 4  
Old 04-01-2011
If your shell is ksh93
Code:
#!/bin/ksh93

NUM=100
for i in {1..$NUM}
do
    printf "Seq%d\nATGCGTA......\n" $i
done

You can also use a sequence expression in bash but the value must be hardcoded into the sequence, i.e. {1..100}, because bash does not apply any syntatic interpretation to the content between the braces.
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