Shell Programming and Scripting

Hi all,

I am looking for a quick solution for this:

I have many log files of an iterative program, and I would like to display the parameters of the last three iteration from each of those files. Relevant lines have the keyword: ITER
I am using:

Code:

tac ~/modeling*/fitting.log | grep -m 3 -e ITER | tac

This works fine for the first directory, modeling1, and returns:

Code:

#f#N  28497.4 0.848 ITER  2.041
#f#N  28497.4 1.034 ITER  2.915
#f#N  28497.4 1.869 ITER  4.165

Is there any similarly simple one liner to get all of them? I have 8 directories, so I expect 24 lines of output.

Thank you!
Peter

May work for you:

Code:

find ~/modeling* -name "*.log"|xargs -ix bash -c "tac x|grep -m 3 -e ITER"

Thank you very much, you saved me a lot of time! It helped and this works perfect:

Code:

find ~/modeling*/fitting.log |xargs -ix bash -c "tac x|grep -m 3 -e ITER|tac"

cheers