awk script to return the middle line number


 
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# 8  
Old 03-31-2011
Hi jontjioe,

Another with awk:

Code:
awk '{nr=NR%2?(NR-1)/2+1:NR/2;a[NR]=$1}END{print a[nr]}' file1

Regards.
This User Gave Thanks to cgkmal For This Post:
# 9  
Old 04-07-2011
you may try below

for i in *;do
lines=`cat $i | wc -l`
line=$(($(($lines/2))+$(($lines%2))))
sed -n "$line{p;}" $i | awk '{print $1}'
done
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