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How to strip '$' sign on the line

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# 1  
Old 03-30-2011
How to strip '$' sign on the line
echo "dddd$dddd"|sed 's/$//' will return dddd
echo "dddd$ddd"|tr -d '$' will return dddd

I need to replace it with any other character or just live a blank space instead

Thank you!
Last edited by Franklin52; 03-31-2011 at 06:39 AM.. Reason: Code tags
# 2  
Old 03-30-2011
Code:
$ echo 'dddd$dddd'| ruby -e 'print gets.split("$").join(" ")'
dddd dddd

# 3  
Old 03-30-2011
Thanks for the prompt reply. Though I need to use ksh commands. (sorry for omitting that)
# 4  
Old 03-30-2011
because when you echo it, you don't get the full chars.

Code:
$ echo "dddd$dddd"
dddd

try this:
Code:
$ echo "dddd\$dddd"|sed 's/\$//'
dddddddd

# 5  
Old 03-30-2011
this obviously works but I unable to put \ in front of $ as the string generated by others.

---------- Post updated at 12:04 PM ---------- Previous update was at 12:02 PM ----------

also I probably could have used awk to spilt it by $ and rejoin it but I don't know how many of them could be there. No I can't. As you noticed it just does not read beyond the $ so ...
Last edited by zam; 03-30-2011 at 10:41 PM..
# 6  
Old 03-30-2011
Quote:
Originally Posted by zam
echo "dddd$dddd"|sed 's/$//' will return dddd
echo "dddd$ddd"|tr -d '$' will return dddd

I need to replace it with any other character or just live a blank space instead

Thank you!
Problem is shell is replacing $ddd with contents of ENV var ddd before string even gets to sed (or awk):

Code:
$ ddd=OOps!
$ echo "dddd$ddd"
ddddOOps!
$ echo 'dddd$ddd'
dddd$ddd

# 7  
Old 03-30-2011
Thanks Smilie I get it ! . But it does make life easy as I have no idea what will be placed after $. It will be different all the time
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