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perl -MConfig -e 'print "$Config{byteorder}\n";'

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# 1  
Old 03-30-2011
perl -MConfig -e 'print "$Config{byteorder}\n";'
What exactly is this code returning:
Code:
perl -MConfig -e 'print "$Config{byteorder}\n";'

I am executing this command in two platforms.
In AIX i am getting : 4321
In Linux i am getting: 12345678

Does it mean that a byte size in aix is of 4 bits(is it possible)?

Also, will there be any difference between length of multibyte character in these platform because of the diff. in the byteorder of 2 platforms ?
Last edited by Franklin52; 03-30-2011 at 08:43 AM.. Reason: Please use code tags
# 2  
Old 03-30-2011
Hi.

It has to do with "endianness".

If your Linux was built (is running) on Intel, that's little-endian.

AIX is big-endian.

From perldoc:

Code:
Byteorders "1234" and "12345678" are little-endian; "4321" and "87654321" are big-endian.

# 3  
Old 03-31-2011
ok, i understand
then what will be the diff. between byteorders 1234 and 12345678
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