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Help with case (Shell: sh)

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# 1  
Old 03-28-2011
Help with case (Shell: sh)
Help with case

Hello I need some help with case since most of the examples I found are related to a choice menus

I have 2 files (actually a lot of files with the specified prefix) in my dir e.g file1 & file2

I need to display:
case1:if file1 & file2 exist :file1_no=$(ll file1 |wc -l); file2_no=$(ll file2 |wc -l);((total=file1_no+file2_no));echo $total;;
case2:if only file1 exist:echo $(ll file1 |wc -l);;
case3:if only file2 exist:echo $(ll file2 |wc -l);;
case4:if both files missing: echo No files received

I need this to avoid the file not found in the report I need to create.

Thank you in advance.
Last edited by drbiloukos; 03-28-2011 at 06:42 AM..
# 2  
Old 03-28-2011
Instead of case use IF-ELIF-FI.
Code:
[[ -f file1 && -f file2 ]] && echo "both files available"
[[ -f file1 && ! -f file2 ]] && echo "file1 available"
[[ ! -f file1 && -f file2 ]] && echo "file2 available"
[[ ! -f file1 && ! -f file2 ]] && echo "files missing"

# 3  
Old 03-28-2011
Since I need to count and report the number of files I want to use case so I can have more than an echo commands available, in order to count and do a total.

I need somthing like this:

Code:
case
[[ -f $fname.$DATE_YYMMDD*.Z && -f $*_prev.$DATE_YYMMDD*.Z ]] fname_no=$(ll $fname.$DATE_YYMMDD*.Z | wc -l);fname_prev_no=$(ll $*_prev.$DATE_YYMMDD*.Z | wc -l
);((total=fname_no+fname_prev_no));echo $fname: $fname_no + $*_prev: $fname_prev_no = $total;;
[[ -f $fname.$DATE_YYMMDD*.Z && ! -f $*_prev.$DATE_YYMMDD*.Z ]] echo $(ll $fname.$DATE_YYMMDD*.Z | wc -l);;
[[ ! -f $fname.$DATE_YYMMDD*.Z && -f $*_prev.$DATE_YYMMDD*.Z ]] echo $(ll $*_prev.$DATE_YYMMDD*.Z | wc -l);;
[[ ! -f $fname.$DATE_YYMMDD*.Z && ! -f $*_prev.$DATE_YYMMDD*.Z ]] echo No files received;;
esac

Will this work ?
Last edited by drbiloukos; 03-28-2011 at 07:59 AM..
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