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sed command, look for numbers following letters

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Top Forums Shell Programming and Scripting sed command, look for numbers following letters
# 8  
Old 03-28-2011
Quote:
Originally Posted by ctsgnb
@tene,

You can get the same result with more simple statement

Code:
sed 's/[0-9][0-9]*$/&/' infile

or even ( a bit less strict)
Code:
sed 's/[0-9]*$/&/' infile

Both these commands are not working.There is no change in output.
# 9  
Old 03-28-2011
Which OS / shell do you run ?
# 10  
Old 03-28-2011
Quote:
Originally Posted by tene
Both these commands are not working.There is no change in output.
Hi tene,

In every post there is something to learn, I didn't know about the ctsgnb solution. I learned how acts "&" here.

first part /[0-9]*$/ looks pattern desired and second part /&/ print the pattern you arent searching and the pattern you search
in first part and in this formsed 's/[0-9]*$/&/'looks like nothing happens. But when you do sed 's/[0-9]*$/& &/' we can see how the
"&" stores the pattern matched, lets without touch the other part and print how we actually want, then:

Pattern not matched=Pnm
pattern matched=Pm=[0-9]*$
output desired=PnmPM Pm=Pnm&" "&

PnmPm=[0-9]*$Output=PnmPm" "Pm=Pnm&" "&
F231F231 231
H42H42 42
1C101C10 10
1F1131F113 113
GreatSmilie!!!

Hope it helps.

Regards
Last edited by cgkmal; 03-28-2011 at 05:53 AM..
# 11  
Old 03-28-2011
@ctsgnb
I ran in bash.
# 12  
Old 03-28-2011
@tene

Oooops, you true, lol! ... i mixed with the initial statement, Smilie

but what you propose can still be simplified this way:

Code:
sed 's/.*[^0-9]//' infile

# 13  
Old 03-28-2011
Yes right, but here we cannot print the original string.
Anyways, I was just trying out the \2 thing in my command..
I am just exploring different ways.
# 14  
Old 03-28-2011
I think the best way to do it is what i proposed in post #4

( the one that cgkmal comments in detail in his post #10)
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