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Shell Programming and Scripting

Finding Last Occurance Of a Char

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# 1  
Old 03-21-2011
Finding Last Occurance Of a Char
Hi,

I need to fine out the Last occurance of / in the following out out.
Code:
crontab -l | grep RMAN_VTL_Bkup.sh | tail -1 | awk '{print $6}'
/oracle/PI1/software/RMAN/backup/RMAN_VTL_Bkup.sh

Coudl you please let me know

Thanking you inadvance,
Last edited by Franklin52; 03-21-2011 at 04:45 AM.. Reason: Please use code tags
# 2  
Old 03-21-2011
Something like this?
Code:
crontab -l | awk -F"/" '/RMAN_VTL_Bkup.sh/{s=$NF}END{print s}'

# 3  
Old 03-21-2011
From the following string I need to Find the last occurance of /. the last occurance is after the backup word. i want to know the posisiting of /.


/oracle/PI1/software/RMAN/backup/RMAN_VTL_Bkup.sh
# 4  
Old 03-21-2011
Give an example of the output of crontab -l and the desired output.
# 5  
Old 03-21-2011
Could this help you?
Code:
var='/oracle/PI1/software/RMAN/backup/RMAN_VTL_Bkup.sh'
echo $(($(expr length $(echo ${var%/*}))+1))

# 6  
Old 03-21-2011
This is the entry in the cron. I am trying to implement one script for which we need
some Input from .env file. env file contain some variable those could be usefull in my scirpy.like ORACLE_HOME,SID,BACKUP_TYP..etc

45 02 24 02 4 /oracle/PQR1/oracle/Rman/backup/RMAN_VTL_Bkup.sh tapebackup_PI1_Arch.env
# 7  
Old 03-21-2011
This is really unclear, please redefine your question.
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