Shell Programming and Scripting

Hi,

I would like to return the last part of a string in an array of strings in bash.

The array contains in each position the content below:

and I would like to return only the last part of each string.
The correct result would be:

How can I do that in bash using AWK?

Thanks and Regards
Anish Kumar.V

In bash

Code:

#!/bin/bash
A=(a.b.c a.d.f a a.d a.b.c.h )
for w in ${A[@]}
do
    echo ${w##*.}
done

In bash using awk:

Code:

#!/bin/bash
A=(a.b.c a.d.f a a.d a.b.c.h )
for w in ${A[@]}
do
    echo $w
done | awk -F. '{print $NF}'

Code:

awk -F \. '{print $NF}' infile

Code:

while read line;do echo ${line##*.};done < file

or using awk

Code:

awk -F. '{$0=$NF}1' file

Hi dude!!

Thanks for your reply, Is it possible to get the output from file instead of directly declaring

Code:

A=(a.b.c a.d.f a a.d a.b.c.h )

like this

A= /root/filename

With Regards
Anish Kumar.V

Code:

#!/bin/bash
A=( $(<file) )
for w in ${A[@]}
do
    echo ${w##*.}
done

Hi all

Thanks for all your replies It works like charm!!! :-)

With Regards
Anish Kumar.V