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How to call multiple variables in bash !!

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# 1  
Old 03-18-2011
How to call multiple variables in bash !!
Hi all ,

I have a file with below data ,
Code:
bash#cat file.txt 
user1  amount1  status1
user2  amount2  status2
user3  amount3  status3
user4  amount4  status4
.
.
.

Now i have a command to be executed with above values like below ,
Code:
  ./errorcheck -u user1 -a amount1 -s status1
  ./errorcheck -u user2 -a amount2 -s status2
  ./errorcheck -u user3 -a amount3 -s status3

How to put these variables on this command so with one command i can execute all the checks ?

Thanks
Last edited by Franklin52; 03-18-2011 at 05:51 AM.. Reason: Please use code tags
# 2  
Old 03-18-2011
Code:
awk '{printf "./errorcheck -u %s -a %s -s %s\n",$1,$2,$3}' file.txt |sh

# 3  
Old 03-18-2011
Code:
while read user amount status; do
  ./errorcheck -u "$user" -a "$amount" -s "$status"
done < file.txt

# 4  
Old 03-18-2011
Hi gnanasekar_beem,

Another similar way:
Code:
awk '{print "./errorcheck -u",$1,"-a",$2,"-s",$3}' file.txt > . commands_to_send.sh
. commands_to_send.sh

Regards
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