Shell Programming and Scripting

great! I didn't even think of the ":" as FS .... stupid...
but anyway this is not what he wanted..

is there any way to make this with grep and some regular exp.

try

Code:

grep '^...[02468]' inputfile

i m very sorry that i couldn t explain it good !

ur grep might get other even numbers from the line , but the numbers at the beginnig of lines are the line numbers of a txt file ,in that line there might be other numbers similar to line number so i only want to get the evenly line numbers ,and common point of those numbers in each line is ":" , i tried many regex with ":" in it but didn t work.. like grep '[0-9]*[02468]:' list.txt but didn t work

Post sample input file removing the line numbers and the expected output.

ok , i start from very beginning ;

imagine i have a text with 3700 lines

"You are to write a script that takes a file name and a word as
input. You will then locate all lines within the file ($1) which
contain that word ($2) -- but there is a twist. The word must
appear at the END of the line, but not exactly: there must be a
period after the word.
In other words, you are finding all lines which have the given
word as the last word in a sentence, with this sentence finishing
at the end of the line also.

But you are not done. You will filter your above grep results so
that you only consider matches on the evenly number lines."

then i will get the middle line among all of these even numbered matches "


that s the work i have to do , this is the original explanation

what you need to find out ?? 1) Lines with even line number OR 2) Lines containing word(provided as input) at the end of line. OR 3) BOTH