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Shell Programming and Scripting

find a user on the system

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# 1  
Old 03-15-2011
find a user on the system
i am prompting for a name to search.

Code:
read user
if [ grep "^$user"   /etc/passwd ]
then

however, i get this error:

Code:
please enter a username on the system:
fool
menu_script2.sh: line 123: [: ^fool: binary operator expected

# 2  
Old 03-15-2011
Try:
Code:
read user
grep "^$user" /etc/passwd > /dev/null 2>&1
if [ $? == "0" ]
then

# 3  
Old 03-15-2011
dont work
# 4  
Old 03-15-2011
Quote:
if [ grep "^$user" /etc/passwd ]
Code:
grep "^$user"   /etc/passwd

alone will print a line from /etc/passwd that matches ^$user. What does that line have to do with logical if test?
You are missing backticks and operator there.
Code:
if [ X`grep "^$user" /etc/passwd` != X ] ; then #user found in /etc/passwd

# 5  
Old 03-15-2011
thank you mirni
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