Shell Programming and Scripting

Hello,

I need to remove a substring from a string in a ksh script, the string is like this:

Code:

LOCATION=+DATADG1/CMSPRD1/datafile/system.235.456721

or

Code:

LOCATION=/u03/oradata/CMSPRD/SYSTEM.dbf

I need to strip the last file name from that path, and get:

Code:

+DATADG1/CMSPRD1/datafile

or,

Code:

/u03/oradata/CMSPRD

I experimented with

Code:

expr index "$LOCATION" SYSTEM

trying to get the position of the "system" string and then use

Code:

substr $LOCATION $position

but the index part didn't work to begin with.

I also experimented with:

Code:

echo ${LOCATION#system}
echo ${LOCATION%%SYSTEM}

they didn't work to substract "sytem" or "SYSTEM" (they could be either lower case or upper case).

Your help is much appreciated.

-Jay

Try DIR=$(basedir $STRING)

Or you can do something like:

Code:

string='LOCATION=/u03/oradata/CMSPRD/SYSTEM.dbf'
newstring=$(echo "$string" | sed 's!.*=\(.*\)/.*!\1!')

You can remove the last "/" and everything that follows it with:

Code:

echo "${LOCATION%/*}"

Regards,
Alister

Thanks for your quick reply. It looks that I don't have basedir in ksh:

$ basedir $LOC
ksh: basedir: not found

but I have basename:

LOC=/db1/data/CMSDEV/SYSTEM.dbf

$ print $(basename ${LOC})
SYSTEM.dbf

That gets me the file name, while I need the dir path/name.

Code:

string='LOCATION=/u03/oradata/CMSPRD/SYSTEM.dbf'
x=${string#*=}
newstring=${x%/*}

edit: Misunderstood question.

Try:

Code:

echo ${LOCATION%/*}

echo "${LOCATION%/*}"
returns empty/null

---------- Post updated at 12:09 PM ---------- Previous update was at 11:44 AM ----------

this returns empty/null as well:

$ echo "$LOCATION" | sed 's!.*=\(.*\)/.*!\1!'

which makes me wonder if there is some shell env variable that needs to be set for this and the previous

echo "${LOCATION%/*}"

?