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Create a list of directory contents

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# 1  
Old 03-09-2011
Create a list of directory contents
Well I did a search and didn't anything for my specific case.

I got a directory with a bunch of text file. All of them have the following pattern on the filename "ABCD_<As of Date>.txt"
Example:
ABCD_20110301.txt
ABCD_20110302.txt
ABCD_20110303.txt



All I want to accomplish is a Korn Shell Script that outputs the list separated with a comma. I know that is very easy to accomplish but I'm having a very hard time understanding shell scripting.

Output Example:
ABCD_20110301.txt,ABCD_20110302.txt,ABCD_20110303.txt


Thank you all for your help.
# 2  
Old 03-09-2011
You could pipe your ls output through paste. i.e.:
Code:
ls ABCD_* | paste -sd, -

Or (if your ls command has the -m option):
Code:
ls -m ABCD_*

This User Gave Thanks to Scott For This Post:
Shark Tek
# 3  
Old 03-09-2011
Quote:
Originally Posted by Shark Tek
Well I did a search and didn't anything for my specific case.

I got a directory with a bunch of text file. All of them have the following pattern on the filename "ABCD_<As of Date>.txt"
Example:
ABCD_20110301.txt
ABCD_20110302.txt
ABCD_20110303.txt



All I want to accomplish is a Korn Shell Script that outputs the list separated with a comma. I know that is very easy to accomplish but I'm having a very hard time understanding shell scripting.

Output Example:
ABCD_20110301.txt,ABCD_20110302.txt,ABCD_20110303.txt
Code:
list=$(printf "%s," *.txt)
printf "%s\n" "${list%,}"

This User Gave Thanks to cfajohnson For This Post:
Chubler_XL
# 4  
Old 03-09-2011
Nice solution wasn't aware that printf worked like that - the C version dosn't.
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