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Grepping from a point in a file to the end of the file

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Top Forums Shell Programming and Scripting Grepping from a point in a file to the end of the file
# 1  
Old 03-09-2011
Grepping from a point in a file to the end of the file
does any one know how to turn the equivalent of this command:

Code:
awk '/2011 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"

to

something that would use egrep instead of awk?

What the awk command does is, it searches the ops.log file for "2011 John Doe 8344". When it finds it, it will output all the lines (ALL), after that string to the screen.

doesn't even have to be egrep. anything but awk. Looks like awk takes too long if the file is huge.
# 2  
Old 03-09-2011
Have you looked at the -A option of grep?
# 3  
Old 03-09-2011
Or using quotes:

Code:
ant:/home/vbe $ more tst00001                     
     1  awk '/2011 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"
     2  awk '/201 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"
     3  awk '/211 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"
     4  awk '/011 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"
     5  awk '/11 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"
     6  awk '/2012 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"
     7  awk '/2013 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"
     8  awk '/2021 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"
     9  awk '/2011 John Dee 8344/,0' /tmp/ops.log | egrep -c "received request"
    10  awk '/2011 John Die 8344/,0' /tmp/ops.log | egrep -c "received request"
    11  awk '/2011 John Dae 8344/,0' /tmp/ops.log | egrep -c "received request"
    12  awk '/2011 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"
ant:/home/vbe $ grep "2011 John Doe 8344" tst00001
     1  awk '/2011 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"
    12  awk '/2011 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"

(HPUX11.11...)
Last edited by vbe; 03-09-2011 at 10:56 AM.. Reason: added OSversion...
# 4  
Old 03-09-2011
Quote:
Originally Posted by joeyg
Have you looked at the -A option of grep?

i tried that.
its either i dont know how to use it properly, or its not working.

---------- Post updated at 10:25 AM ---------- Previous update was at 09:53 AM ----------

Quote:
Originally Posted by vbe
Or using quotes:

Code:
ant:/home/vbe $ more tst00001                     
     1  awk '/2011 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"
     2  awk '/201 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"
     3  awk '/211 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"
     4  awk '/011 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"
     5  awk '/11 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"
     6  awk '/2012 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"
     7  awk '/2013 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"
     8  awk '/2021 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"
     9  awk '/2011 John Dee 8344/,0' /tmp/ops.log | egrep -c "received request"
    10  awk '/2011 John Die 8344/,0' /tmp/ops.log | egrep -c "received request"
    11  awk '/2011 John Dae 8344/,0' /tmp/ops.log | egrep -c "received request"
    12  awk '/2011 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"
ant:/home/vbe $ grep "2011 John Doe 8344" tst00001
     1  awk '/2011 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"
    12  awk '/2011 John Doe 8344/,0' /tmp/ops.log | egrep -c "received request"

(HPUX11.11...)


this will only output all lines matching john doe 8344. i want ALL lines that comes AFTER the specified string is found regardless of if the lines have the specified string on them or not.
# 5  
Old 03-09-2011
Can you post sample input and expected output.
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