As we know in regular expression, [^ab] means neither a nor b.
Now the question is how to consider <ab> as a whole part or somehow a single char. Something like [^(ab)] which is meaning neither ( nor a nor b nor ).
Or do we have another way for this?
The real requirement is as below:
example1 :
I know below expression to count the number of semicolon which is inside / pair or * pair
my @cnt = $str =~ /;
(?=
(?:[^\/]*$) (?# there is no \/ after ; )
|
(?: (?:[^\/]*?\/[^\/]*\/[^\/]*)*$) (?# if have \/ after ;, must appear in pair)
)/gx;
Here i am struggling with the red highlighted part, which means not </>, how can we make it somehow mean not </*>?
Please help. Thanks in advanced
Last edited by summer_cherry; 03-08-2011 at 06:21 AM..
Would this work..to mean no ab's together?
And in unix regexp (not sure with Perl)we do not need to escape special characters when given within square brackets.Please remove those escape characters present within square brackets and try. I also did not understand where you struggle, can you elaborate?
---------- Post updated at 04:43 PM ---------- Previous update was at 04:15 PM ----------
Try the below reqexp using save-part. It matches anything in between, including /*..*/
Hi ,
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Hi I am doing something basic like...
if ($stringvariable =~ /have not typed/)
I have a little problem because the 'not' in the expression gets highlighted as a kind of a '!'..what am I supposed to do in this situation?
Thank you
---------- Post updated at 03:24 PM ----------... (1 Reply)
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{
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}
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1111
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zz
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