Shell Programming and Scripting

I want to get IP address only from the input using sed. i.e string between between "(" and ")" delimeters.

Code:

 
echo "serverA (11.22.333.444) is alive" | sed 's/<??>/<??>/'

I know how to do this using cut and awk's split features.

I also want to know how to do this using awk's multiple delimeter seperator syntax using something like FS="[(|)+]" but its not working [ echo "serverA (11.22.333.444) is alive" | gawk '{ FS = "[()]+" } { print $1 }' ].

Code:

sed 's/.*(//; s/).*//'

Code:

awk -F '[()]' '{print $2}'

Regards,
Alister

Code:

echo "serverA (11.22.333.444) is alive" |grep -Eo '[0-9]{2}.[0-9]{2}.[0-9]{3}.[0-9]{3}'
11.22.333.444

Thanks alister, both sed and awk are working perfect.

yinyuemi,
Specific version of grep/egrep/fgrep I have on Solaris8 even under /usr/xpg4/bin does not have -o option available. Thanks for posting,, I did not know we can specify number characters using {#N} notation.. I am wondering if that is valid in regex for sed, awk also.!?