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~~Unix command to count a particular word in the whole directory .~~

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# 1  
Old 03-05-2011
Question ~~Unix command to count a particular word in the whole directory .~~
Hi ,

i'm trying to count a particular word occurance in a whole directory..is this possible Smilie

say for example there is a directory with 100 files which and all the file may have the word 'aaa' in it ...how would i count the number of 'aaa' in those whole 100 files in a directory ?

thanks for your help
# 2  
Old 03-05-2011
Quote:
Originally Posted by Rabbitsfoot
is this possible Smilie
Impossible is nothing... with Perl Smilie
Try:
Code:
cd /your/dir
perl -ne '$x+=s/\baaa\b//g;END{print "$x\n"}' *

# 3  
Old 03-05-2011
thanks ..that looks promising :) ...is there an alternate if i dont have perl installed ..
# 4  
Old 03-05-2011
What system are you using? Try this:
Code:
awk '{n+=gsub("aaa","")}END{print n}' *

That code is imperfect though (in oposite to Perl oneSmilie), as it will treat words like "aaaaaa" as two "aaa" words. Perl one-liner is not counting those words.
# 5  
Old 03-05-2011
Code:
cat * | tr '[:blank:]' '[\n*]' | grep -Fx aaa | wc -l

Last edited by alister; 03-05-2011 at 04:05 PM..
# 6  
Old 03-05-2011
@ bartus11 :- excellent that perl command worked great ..!! i'm using Solaris 5.10 ..


@ alister ..looks like it is throwing error as it is unable to find the directory ..i ran the perl and ur command at the same directory
# 7  
Old 03-05-2011
Quote:
Originally Posted by bartus11
What system are you using? Try this:
Code:
awk '{n+=gsub("aaa","")}END{print n}' *

That code is imperfect though (in oposite to Perl oneSmilie), as it will treat words like "aaaaaa" as two "aaa" words. Perl one-liner is not counting those words.
then you iterate each word using for loop. Perl is overhyped when it comes to text/string processing
Code:
awk '{for(o=1;o<=NF;o++) if ( $o == "aaa") c++}END{print c}'  file

similarly, if OP have Ruby ( which most probably not)
Code:
$ ruby -e 'print "aaa aaa tes aaaa".scan(/\baaa\b/).size'
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