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sed command : print lines having no # at the begining

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# 1  
Old 02-28-2011
sed command : print lines having no # at the begining
I am trying to print those line which has no # in the begining of the line.
The sed I used for this purpose as shown below is not giving the required output.

Code:
echo 'PDE 5600' | sed -n 's/^\!#/&/p'

Where lies the problemSmilie
Last edited by hiten.r.chauhan; 02-28-2011 at 04:02 AM.. Reason: error in typing
# 2  
Old 02-28-2011
Code:
sed -n '/^[^#]/p'

# 3  
Old 02-28-2011
Code:
$ echo 'PDE 5600' | ruby -e 'print  if !gets[/^\s+#/] '
PDE 5600
$ echo '   #PDE 5600' | ruby -e 'print  if !gets[/^\s+#/] '
$ echo '   #PDE 5600' | ruby -e 'print  if !gets[/^\s+#/] '
$

# 4  
Old 02-28-2011
BY GREP
Code:
grep -v ^#

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