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Cutting file name from end

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# 1  
Old 02-24-2011
Cutting file name from end
Dear Friends,

I want to take last 10 characters of a file name in a variable.

E.g.
file name is
123432311234567890.txt
then we want "1234567890" to be taken in an variable.

Request you to guide me to do the same

Thanks in anticipation

Anushree
# 2  
Old 02-24-2011
try
Code:
$ a=123432311234567890.txt
$ expr $a : '.*\(..........\).txt'
1234567890
$

# 3  
Old 02-24-2011
one way:

Code:
#  echo "123432311234567890.txt" | nawk -F. '{print substr($1,length($1)-9,10)}' 
1234567890

# 4  
Old 02-24-2011
Code:
# a=123432311234567890.txt
# a=${a%.*};t=${a%??????????};echo "${a#$t}"
1234567890

Code:
# echo "123432311234567890.txt" | sed 's/.*\(.\{10\}\)\.txt/\1/'
1234567890

Code:
# a=123432311234567890.txt
# typeset -R10 a=${a%.*}
# echo $a
1234567890

Last edited by ctsgnb; 02-24-2011 at 09:18 AM..
# 5  
Old 02-24-2011
Code:
 var=$(echo "123432311234567890.txt"  | ruby -e 'puts gets.split(/\./)[0..-2].join(".")[-10..-1]')

# 6  
Old 02-25-2011
through sed..
Code:
STR=$(echo "123432311234567890.txt"|sed 's/.*\(.\{10\}\).txt/\1/')

# 7  
Old 02-25-2011
Or...
Code:
STR=$(basename 123432311234567890.txt .txt | tail -c 11)
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