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GREP/SED - get string in a line

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# 8  
Old 02-22-2011
could also try a funny
Code:
grep "/folderA/folderB" INPUT_FILE | xargs -n1 | sed '/folder/!d'

or
Code:
grep "/folderA/folderB" INPUT_FILE | xargs -n1 | sed '/\//!d'

Smilie

Code:
# cat tst
lines not needed....
start_1 /folder1/folder2/folder3/file_a end_1
start_2 /folder1/folder2/folder3/folder4/file_b end_2
start_3 /folder1/folder2/folder3/folder4/file_c end_3
lines not needed....

Code:
# grep folder tst | xargs -n1 | sed '/\//!d'
/folder1/folder2/folder3/file_a
/folder1/folder2/folder3/folder4/file_b
/folder1/folder2/folder3/folder4/file_c

# 9  
Old 02-22-2011
I had a look in the man pages... but did not get it completly...

could you please explain me exactly what ...
1.)
Code:
!d

does?
2.)
Code:
xargs -n1

does?
# 10  
Old 02-22-2011
xargs -n1 displays 1 string per line
sed '/\//!d' will delete every lines that do NOT contain a slash (the negation "NOT" is specified by the bang"!")
This User Gave Thanks to ctsgnb For This Post:
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