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set -options not working inside for loop?

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# 1  
Old 02-17-2011
set -options not working inside for loop?
I'm a beginner in shell scripting (I'm using ksh). I'm manipulating some files and I'm using set -A to transform each read line into a numeric array.
However, inside the 'for' loop the options of set (ie '-A') are not recognized (the vi editor doesn't highlight it and it doesn't work).

Where is my error?

My data.entry.* files are of the format:
Code:
   2 number_of_variables
-1.654824e+02    x1
-2.4685125e+01   x2

Code:
FILEIN="data.entry."   # I've got files named like data.entry.34
FILEOUT="global_entries"
 
files=`ls $FILEIN* | cut -d "." -f 3 | sort -n`
set -A F $files                      #THIS set -A works properly
FirstEvaluation=${F[0]}
echo $FirstEvaluation First_Evaluation_Number > $FILEOUT
 
for f in $files; do
   let "count=0"
   VarsArray=" "
   while read myline;
   do
 if (($count == 0));then 
    set -A WORDS $myline   # The -A is not recognized as a set option!?
    let "NumVars=${WORDS[0]}"
 elif (($count <= $NumVars));then
    set -A WORDS $myline     # The -A is not recognized as a set option!?
    VarX=${WORDS[0]}
           VarsArray=$VarsArray"    "$VarX
 else
    break
 fi
 ((count++))
   done < $FILEIN$f
 
   echo $VarsArray >> $FILEOUT 
done

# 2  
Old 02-17-2011
Code:
#!/usr/bin/ksh

Should be the first line of your script (if you want make sur you run it in ksh)
of course adapt the path if necessary

---------- Post updated at 12:55 PM ---------- Previous update was at 12:32 PM ----------

instead of:
Code:
if (($count == 0));then
...
elif (($count <= $NumVars));then

try
Code:
if (( $count == 0 ));then
...
elif (( $count <= $NumVars ));then

If you have some error message when running your script, please post them
# 3  
Old 02-17-2011
The line
Code:
#!bin/ksh

was already in the code, I forgot to post it...

I used this file as a test:
Code:
                                          2 variables
                     -1.992929132651970e+00 x1
                     -2.621936892448895e-02 x2

and when running the shell i get:

Code:
./EvalShell.sh[43]: set: -1: unknown option
./EvalShell.sh[43]: set: -.: unknown option
./EvalShell.sh[43]: set: -9: unknown option
./EvalShell.sh[43]: set: -9: unknown option
./EvalShell.sh[43]: set: -2: unknown option
./EvalShell.sh[43]: set: -9: unknown option
./EvalShell.sh[43]: set: -2: unknown option
./EvalShell.sh[43]: set: -9: unknown option
./EvalShell.sh[43]: set: -1: unknown option
./EvalShell.sh[43]: set: -3: unknown option
./EvalShell.sh[43]: set: -2: unknown option
./EvalShell.sh[43]: set: -6: unknown option
./EvalShell.sh[43]: set: -5: unknown option
./EvalShell.sh[43]: set: -1: unknown option
./EvalShell.sh[43]: set: -9: unknown option
./EvalShell.sh[43]: set: -7: unknown option
./EvalShell.sh[43]: set: -0: unknown option

Line 43 corresponds to the line of the second "set -A WORDS $myline" in the for loop.
It seems the input for the set options are the digits of the number in the entry test file... I have no idea why this happens!
# 4  
Old 02-17-2011
Code:
#!bin/ksh

?
or
Code:
#!/bin/ksh

?

Did you post your whole script or just a part of it ???

The error you get suggest a problem line 43 and what you posted dooesn't exceed 38 lines
# 5  
Old 02-17-2011
Yes, it is actually
Code:
 
#!/bin/ksh

That's the whole script (without comments)
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