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Extracting the Root Element from the XML File

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# 1  
Old 02-15-2011
Extracting the Root Element from the XML File
Any help to extract the root element from an XML file will be appreciated.

Example: test.xml
Code:
<?xml version="1.0" encoding="utf-8" ?> 
<TestXMLMessage>
<TestRec>
<ID>1000</ID> 
</TestRec>
</TestXMLMessage>

Wanted to extract the TestXMLMessage.

Regards,

Chari
Last edited by Franklin52; 02-15-2011 at 04:23 AM.. Reason: Please use code tags
# 2  
Old 02-15-2011
Something like this?
Code:
awk -F"[<>]" 'NR==2{print $2}' file

or maybe this what you mean:
Code:
awk '/<TestXMLMessage>/{f=1};f;/<\/TestXMLMessage>/{f=0}' file

Last edited by Franklin52; 02-15-2011 at 04:43 AM..
This User Gave Thanks to Franklin52 For This Post:
sree_chari
# 3  
Old 02-15-2011
Could this help you?
Code:
awk '{if(/^<TestXMLMessage>/){print;flg=1;next} if(flg==1) {print;next} if (/^<\/TestXMLMessage>/){print;flg=0}}' test.xml

# 4  
Old 02-15-2011
Quote:
Originally Posted by Franklin52
Code:
awk '/<TestXMLMessage>/{f=1};f;/<\/TestXMLMessage>/{f=0}' file

This can be done a bit shorter:
Code:
awk '/<TestXMLMessage>/,/<\/TestXMLMessage>/' file

This User Gave Thanks to bartus11 For This Post:
Franklin52
# 5  
Old 02-15-2011
Here is an XSL stylesheet which prints the root element of the document
Code:
<xsl:stylesheet version="1.0"
   xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

   <xsl:output method="text"/>

   <xsl:template match="/">
      <xsl:value-of select="name(/*)"/>
   </xsl:template>

</xsl:stylesheet>

Using xsltproc to transform the input docuemnt:
Code:
$ xsltproc example.xsl example.xml
TestXMLMessage
$

# 6  
Old 02-15-2011
Hi All,

Thanks for your quick response.

This helped what I wanted to achieve.
Code:
awk -F"[<>]" 'NR==2{print $2}' file

Best Regards,

Chari
Last edited by Franklin52; 02-16-2011 at 05:03 AM.. Reason: Please use code tags, thank you
# 7  
Old 02-23-2011
Hi All,

I am trying to change the XML filename in a folder to the rootelement in the XML file.

Now I have something like this.
Code:
for i in *.xml; do echo $i;awk -F"[<>]" 'NR==2{print $2}' $i; done

Output of above command:
Code:
TestMsg2010-10-19_20_20_54.xml
R1Msg TimeStamp="2010-10-19T08:49:08.000000Z"
TestMsg2010-10-19_20_20_58.xml
R2Msg TimeStamp="2010-10-19T08:49:08.000000Z"

Renamed File OutputSmilieThis is what I want to achieve)
Code:
R1Msg2010-10-19_20_20_54.xml
R2Msg2010-10-19_20_20_58.xml
R3Msg2010-10-19_20_21_00.xml

Is there a way that I can tweak the above command to achieve the same? Please help me as I am new to this side of programming.

Thanks in advance.
Last edited by Franklin52; 02-24-2011 at 03:30 AM.. Reason: Please use code tags
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