Shell Programming and Scripting

Good morning,

I don't use the crontab for this monitoring file... it's called from a scheduler of the application installed on this server. I run it monday to friday between 07:00 and 19:00.
I want to run the script every 5 minutes ...

I can use every date available ... the file is written once and will be overwritten when a new file arrives. There is never a change on the file.

The only thing I need is to check if the file is older than 20 minutes.

If there is a better or easier way than use the epoch time, it's OK for me...
I don't care which technic is used, I just need a solution :-)

Thanks and best regards

Rolf

Perl one-liner to get file age in minutes....

Code:

# ls -l /etc/passwd
-rw-r--r--   1 root     sys         1142 Feb 14 11:35 /etc/passwd
# date
Mon Feb 14 12:47:08 EST 2011
# perl -e 'printf "%d\n", (time - ((stat(shift))[9]))/60;' /etc/passwd
72
#

You can get rid of the "/60" to get the age in seconds.

Or...

Code:

perl -e 'printf "%d\n",(-M shift)*24*60' /etc/passwd

Thank you very much, it works perfect!

I see, I have to learn perl :-)

Best regards

Rolf