Shell Programming and Scripting

This is what i am trying to do. I have a file which has the following

file name-new.txt

*
include "/net/proj/new/1.txt"
include "/net/proj1/new/2.txt"
*

What I would like is to copy the file which is in the include statement
1. Read new.txt
2. copy 1.txt from /net/proj/new and 2.txt from /net/proj1/new/ which is in the include statement.

I have tried by zipping the file but it zips the entire path which doesnt work for me.

thanks in advance.

I'm confused, some words must be missing! Copy where for what? Do you want to preprocess it to include the include files in a temp file with no includes, like cpp or cc -E?

What I meant was while parsing the file, it should find all the places where there is an include statement and whatever is there in the include statement, I should be able to copy that file somewhere, may be temp. The include statement always has a path to a file.

I hope I have explained it better.

Do you need to parse include files for further includes (i.e should the script also check 1.txt and copy any files that it includes)?

Code:

new.txt
  |
  |---> 1.txt
  |       |
  |       ---> 1A.txt
  |
  L---> 2.txt

---------- Post updated at 11:44 AM ---------- Previous update was at 11:36 AM ----------

If not this should do the trick (copies to a temp sub directory under where new.txt is).

Code:

awk '
  /^[ \t]*include "/ {
     file=$0
     sub("[^\"]*\"", "",file)
     sub("\"$","",file)
     system("cp " file " ./temp")}' new.txt

Chubler,

Thanks, let me try it.

Now that you mentioned, 1.txt might have includes too.

Hi

Try this:

Code:

grep include new.txt | sed 's/include *\(.*\)/cp \1 \/temp/' | sh

Guru

Code:

 
cp $(sed -n 's/^include //p' new.txt) /temp