Shell Programming and Scripting

I am using the command

Code:

ls -lhB --group-directories-first --no-group --file-type --time-style=+%D $@ | sed 's/AlphaLexman/ALM/g'

to replace my username with my initials (to keep the width shorter), but if my username is in the filename such as

Code:

report_by_AlphaLexman.txt

it becomes

Code:

report_by_ALM.txt

Is there any way to get sed to only look at the third column in my 'ls' output and not the sixth column. I think I need to use

Code:

awk '{ print $1 $2 sed_something_$3 $4 $5 $6 }

but I am a complete noob with awk!

Original output:

Code:

-644. 1 AlphaLexman 124K 02/08/11 report_by_AlphaLexman.txt

Actual output:

Code:

-644. 1 ALM 124K 02/08/11 report_by_ALM.txt

Desired output:

Code:

-644. 1 ALM 124K 02/08/11 report_by_AlphaLexman.txt

NOTE: I have some other sed's to replace the -rw-r--r--. to -644.

To replace only the first occurrence you should omit the global option:

Code:

sed 's/AlphaLexman/ALM/'

instead of:

Code:

sed 's/AlphaLexman/ALM/g'

Thank you very much, I was making the problem bigger than the solution.