Shell Programming and Scripting

I'm running the script below and get the output below against a file with

Code:

lineA=aaa
lineB=bbb
lineC=ccc
lineD=ddd

I get output:

Code:

lineC=ccc
lineD=ddd

I need the output to be:

Code:

lineB=bbb
lineC=ccc
lineD=ddd

Code:

cat filename | nawk '/lineA=aaa/ {
getline;
do {
getline
print
 } while ( $1 != "lineD=ddd" )
}'

I can go further up the file for my starting value and get what I need but I just need to figure out why it's skipping the first line of what it finds when it prints the output.

Thanks in advance.

You've used two getline's. That's why it doesn't print the first two lines.

Code:

awk '/lineA=aaa/ {
do {
getline
print
 } while ( $1 != "lineD=ddd" )
}' file1

After the second getline, $0 will be the third line (LineC=ccc).

can this code help you?

Code:

 awk '/lineA=aaa/{p=-1}{p++}p' file

Your spec can be described as "Keep printing lines from the one following the first matched to the last matched". You match the first line that you want, so you get a new line (getline), print it and then ask: Is this the line I want to match last? If yes then quit; otherwise, keep getting lines. So, as scottn points out, the first getline, the one that is out of the loop, should not be there because that is not what you want.