Perl Script to execute todays date.


 
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# 1  
Old 02-01-2011
Perl Script to execute todays date.

Hi Folks,

I have created a script last month to retrive files thru FTP and cronjob was running fine till yesterday. But the naming convention of the daily file is Filename_<date>.xml
where date is YYYYMMDD. But today i have received file name as Filename_20110232.xml Smilie

Part of my Perl script to execute above one:
Code:
($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst) = localtime(time)
$date = sprintf("%04d%02d%02d", $year+1900, $mon+1, $yday+1);

Can anyone please suggest me the right way of doing this. Only Perl works no shell Script.

Thanks & Regards
Sendhil Kumaran

Last edited by Franklin52; 02-02-2011 at 03:34 AM.. Reason: Please use code tags, thank you
# 2  
Old 02-02-2011
Hi,

$yday is the day of the year, in the range 0..364 (or 0..365 in leap years.). (i.e.32 means 1st Feb)
and $mday is the day of the month.
# 3  
Old 02-02-2011
Any other suggestions Please
# 4  
Old 02-02-2011
Code:
($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst) = localtime(time)
$date = sprintf("%04d%02d%02d", $year+1900, $mon+1, $mday+1);

# 5  
Old 02-03-2011
Quote:
Originally Posted by Chubler_XL
Code:
($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst) = localtime(time)
$date = sprintf("%04d%02d%02d", $year+1900, $mon+1, $mday+1);

I think that last parameter should be $mday instead of $mday+1.

tyler_durden
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