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need to Delete first 10 characters of a file name

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# 1  
Old 02-01-2011
need to Delete first 10 characters of a file name
Hello Everyone,

I need help in deleting first 10 characters from the filename in a directory

eg:
1234567890samplefile1.txt
1234567890samplefile2.txt
and so on..

need to get the output as
samplefile1.txt

Thanks in Advance!!!!
# 2  
Old 02-01-2011
try:

Code:
for i in `ls *sample*.txt|sed 's/[0-9]*s/s/'`
do
cp *$i $i
done

# 3  
Old 02-01-2011
Hi Olivia,
If it is always first 10 characters to be ignore while printing, below command may help you. List them first and using "cut" command print them from 11th character till end of file name.

ls -1|cut -c 11-

If this is not working, you can have requirement explained more clear.

Cheers,
Chanakya
This User Gave Thanks to Chanakya.m For This Post:
Olivia
# 4  
Old 02-01-2011
Code:
file=1234567890samplefile1.txt

mv $file ${file:10}

# 5  
Old 02-01-2011
Quote:
Originally Posted by yinyuemi
try:

Code:
for i in `ls *sample*.txt|sed 's/[0-9]*s/s/'`
do
cp *$i $i
done

Thanks for your reply but am getting an error as cp 1234567890samplefile1.txt and 1234567890samplefile1.txt are identical

Can you please help me out!!
# 6  
Old 02-01-2011
Quote:
Originally Posted by yinyuemi
try:

Code:
for i in `ls *sample*.txt|sed 's/[0-9]*s/s/'`
do
cp *$i $i
done

breaks on files with white spaces. don't use ls with for loop like that. Use the shell.
Code:
for file in *sample*.txt 
do
  
done

# 7  
Old 02-01-2011
Code:
$ echo 1234567890samplefile1.txt | ruby -e 'print gets[10..-1]' 
samplefile1.txt
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