Help regarding shell script


 
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# 36  
Old 02-06-2011
Mike shoulds like your lsuser command isn't listing usernames and IDs.

from reading the code lsuser should be giving you output something like this:

Code:
$ lsuser -c -a ALL
root:0
daemon:1
bin:2
sys:3
adm:4
...

# 37  
Old 02-06-2011
I don't really understand the problem if there is one? Mike said the code worked and I tested it on AIX and it seemed to be working fine...
# 38  
Old 02-06-2011
I'm just going from Mike's statements:
Quote:
(UID column) doesn't gets displayed though when I run the script.
The UID is the third column which gets removed but the long group name gets displayed
I suspect that the lsuser command is only listing local user ID's and not AD users.

This version of the script might be safer (if UID or GID not found in array then then just diplay the ID instead of blanks).
Code:
ls -n $@ | awk -F: '
function max(a,b) {return a>b?a:b}
function toend(str,fld)
{ for(i=0; i<length(str); i++) {
    while(substr(str,i,1) != " " && i<length(str)) i++
    while(substr(str,i,1) == " " && i<length(str)) i++
    if (!--fld) return substr(str,i)
  }
  return ""
}
BEGIN {
    while("lsuser -c -a id ALL"  | getline) {
        U[$2]=$1; UW=max(UW,length($1))}
    while("lsgroup -c -a id ALL" | getline) {
        G[$2]=$1; GW=max(GW,length($1))}
}
{
    printf "%10s %3s %-*s %-*s %11s %s\n", $1, $2,
      UW, $3 in U?U[$3]:$3,
      GW, $4 in G?G[$4]:$4,
      $5, toend($0,5)
}' FS=" "

# 39  
Old 02-06-2011
Hi S,

Your code worked fine after the tweak. The UID is just displaying in the numeric format but apart from that it is completely fine. Is there anything can be added to the code to make "1750560623" to display the userid "MIKE045" ??

Chubler,

The code S tweaked worked fine. and the following is the output I get as required. And I ran your code too I get the output as displayed below with only the numeric stuff displaying instead of UID MIKE045.. Can that be replaced??

Code:
-rwxrwxr-x    1 1750560623 Func-Wireless-consumers  10 Jan 27 12:21 list.sh
-rwxr-x---    1 1750560623 Func-Wireless-consumers  80 Jan 28 09:25 .desk


Last edited by mike12; 02-06-2011 at 07:18 PM.. Reason: spelling
# 40  
Old 02-06-2011
Mike, what do:
Code:
lsuser -c -a id ALL

and
Code:
lsgroup -c -a id ALL

produce?

Can you give an impression? Are all your long names present in the listing?
# 41  
Old 02-06-2011
Hi S,

When I do for the lsuser I get in the following format :
Code:
#name : id
  mike001: 74861

and so on for all users and for lsgroup
Code:
#name:id
Func-Wireless-Consumers :1399683538 and so on for all the groups

So the group all gets displayed when I run but the user displayed as 74861 instead of mike001.

Thanks
Mike

Last edited by mike12; 02-06-2011 at 08:45 PM.. Reason: corrections
# 42  
Old 02-06-2011
OK, so there are spaces. try this:
Code:
ls -n | 
awk -F: 'BEGIN{
           while("lsuser -c -a id ALL"  | getline){gsub(/ /,x);U[$2]=$1}
           while("lsgroup -c -a id ALL" | getline){gsub(/ /,x);G[$2]=$1}
         }
         { sub($3" +"$4, U[$3]" "G[$4])} 1' FS=" "

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