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Help with variable name

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Top Forums Shell Programming and Scripting Help with variable name
# 1  
Old 01-24-2011
Help with variable name
Hi

I have output from a program like this
average load 14 10 10 8 4 2

I would like an output like this
load1 14
load2 10
load3 10
load4 8
load5 4
load6 2
load7
load8
load9
load10

More number are added behind when load increase (max 10)
I can easy make this with doing the same 10 times, but would like this to be a loop.

My test that did not work
Code:
info=`wget -q -O - "http://server" | grep Load`
for i in `seq 1 10`;
echo -n "load$i "
echo $info | awk '{print "$((i+2))"}'
done

This does not do the i+2, it just print it, no value
Last edited by Jotne; 01-24-2011 at 06:12 AM..
# 2  
Old 01-24-2011
Try like this,

Code:
echo 'average load 14 10 10 8 4 2' | awk '{for(i=1;i<=10;i++) {print $2i,$(2+i)}}'

This User Gave Thanks to pravin27 For This Post:
Jotne
# 3  
Old 01-24-2011
Thanks, it did the job, but I did a small error.
I need
load1.value 11
load2.value 11
etc
How to add value (for munin graphs) in awk line

Edit 1
I did try
echo 'average load 14 10 10 8 4 2' | awk '{for(i=1;i<=10;i++) {print $2i,".value",$(2+i)}}'
But this give
load1 .value 11
I need
load1.value 11
No space...

This:
echo 'average load 14 10 10 8 4 2' | awk '{for(i=1;i<=10;i++) {print "load",i,".value",$(2+i)}}'
gives even more space
load 1 .value 11


Edit 2
Removing "," did remove the space
echo 'average load 14 10 10 8 4 2' | awk '{for(i=1;i<=10;i++) {print "load"i".value",$(2+i)}}'
do give this
load1.value 11
Last edited by Jotne; 01-24-2011 at 07:48 AM..
# 4  
Old 01-24-2011
Try this,
Code:
 echo 'average load 14 10 10 8 4 2' | awk '{for(i=1;i<=10;i++) {print $2i".value",$(2+i)}}'

This User Gave Thanks to pravin27 For This Post:
Jotne
# 5  
Old 01-24-2011
Thanks, works
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