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Print the 2nd line everytime after defined pattern is found.

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# 1  
Old 01-18-2011
Print the 2nd line everytime after defined pattern is found.
Hi,

I have a text file similar to the example below and I want to print the second line every time after the "--------------------------" pattern is found. The pattern is a fixed length of - characters.

Example of input;
Code:
1    --------------------------
2
3    39184018234
4    1093841028934
5    9128348
9    8429834
10
11  --------------------------
23
24  4984598
25  jma8re8
26  98rn8r
27  9n8re8
28
29  --------------------------
30
31  lldskfgkl
32  iriro04049
33  490494
34  lkaskiooir

Desired output;
Code:
3    39184018234
24  4984598
31  lldskfgkl


Thank you!
Last edited by radoulov; 02-22-2011 at 07:42 AM.. Reason: Code tags, please!
# 2  
Old 01-18-2011
Code:
awk '/------------/{nr=NR;next} NR==nr+2' inputFile

# 3  
Old 01-18-2011
Another one:
Code:
awk '/---/{c=2}c--==0' file

# 4  
Old 01-18-2011
Thanks guys!
# 5  
Old 01-18-2011
thru sed..
Code:
sed -n '/----/{N;x;N;s/.*\n//p}' inputfile > outfile

# 6  
Old 01-18-2011
Code:
sed -n '/---/{n;n;p;}' infile

# 7  
Old 02-22-2011
I would like to see whether it is possible to expand my output further.

I have a text file similar to the example below and I want to print the second line every time after the "--------------------------" pattern is found. The pattern is a fixed length of - characters. In addition I would also like to add a word with a sequential number e.g. Item 1, Item 2, Item 3


Input;
Code:
1 --------------------------
2
3 39184018234
4 1093841028934
5 9128348
9 8429834
10
11 --------------------------
23
24 4984598
25 jma8re8
26 98rn8r
27 9n8re8
28
29 --------------------------
30
31 lldskfgkl
32 iriro04049
33 490494
34 lkaskiooir


Desired output;
Code:
Item 1
3 39184018234
Item 2
24 4984598
Item 3
31 lldskfgkl

Last edited by Franklin52; 02-22-2011 at 07:31 AM.. Reason: Please use code tags, thank you
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