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Renaming files

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# 1  
Old 01-15-2011
Renaming files
Can someone please help. Much appreciated!!

I have 4 directories, for ex...

/RUN1/ReportTable.nxt
/RUN2/ReportTable.nxt
/RUN3/ReportTable.nxt
/RUN4/ReportTable.nxt

I would like to write a for loop, to add the directory name to each ReportTable.nxt

I would like for it to be:
/RUN1/Run1_ReportTable.nxt
/RUN2/Run2_ReportTable.nxt
/RUN3/Run3_ReportTable.nxt
/RUN4/Run4_ReportTable.nxt
# 2  
Old 01-15-2011
Try this

create a file called dir and put all the directory names (in your case it is RUN1 and in the next line RUN2 and so on...)

First try this.

just comment the mv command and make sure it gives the correct expected file name in the echo.

mv $j $new_file

Code:
for i in `cat dir`
do
        cd $i;
    for j in `ls`
    do
        new_file=`echo $i\_$j`
        echo $new_file
        #mv $j $new_file
    done
    cd -;
done

# 3  
Old 01-16-2011
Quote:
Originally Posted by itkamaraj
Try this

create a file called dir and put all the directory names (in your case it is RUN1 and in the next line RUN2 and so on...)

First try this.

just comment the mv command and make sure it gives the correct expected file name in the echo.

mv $j $new_file

Code:
for i in `cat dir`
do
        cd $i;
    for j in `ls`
    do
        new_file=`echo $i\_$j`
        echo $new_file
        #mv $j $new_file
    done
    cd -;
done

Uh, there is something wrong with that first line of code. No need to examine the contents of any files with cat, plus you can't cat a directory.
Code:
cat dir
cat: dir: Is a directory

Plus this needs to run from the same directory dir is in so cd dir/$i is necessary. I have no clue what the semicolons are there for so I just removed them. Otherwise this is a nice solution to the problem at hand:
Code:
for i in `ls dir`
do
        cd dir/$i
    for j in `ls`
    do
        new_file=`echo $i\_$j`
        echo $new_file
        #mv $j $new_file
    done
    cd -
done

# 4  
Old 01-16-2011
Using
Code:
for i in `anything`

isn't a nice solution to anything.

And what is the point of:
Code:
new_file=`echo $i\_$j`

when
Code:
new_file=$i\_$j

would do?

And why are there no quotes around variables here:
Code:
mv "$j" "$new_file"

(although I suppose they make no difference as that for-loop can't handle filenames with spaces anyway!)
# 5  
Old 01-16-2011
Very good points there Scottn. When first learning bash or any other shell programing its easy to get focused on just making the code work. There are a lot of gothcha's that can be avoided with a little more thought.

---------- Post updated at 03:02 PM ---------- Previous update was at 01:57 PM ----------

OK, I am still learning this stuff but I think I cleaned it up after taking Scottn's suggestions (works with filenames that have spaces). Plus I learned a lot from the whole process.

Code:
cd dir
for i in *
do
  cd "$i" >/dev/null
  for j in *
  do
    new_file=$i\_$j
    echo mv "$j" "$new_file"
    #mv "$j" "$new_file"
  done
  cd - >/dev/null
done

# 6  
Old 04-08-2011
Code:
user:RUN$ ls
RUN1    RUN2    RUN3    RUN4
user:RUN$ for i in `ls`;do for j in `ls $i`; do mv $i/$j "$i"_"$j";done;done
user:RUN$ ls
RUN1            RUN2            RUN3            RUN4
RUN1_ReportTable.nxt    RUN2_ReportTable.nxt    RUN3_ReportTable.nxt    RUN4_ReportTable.nxt

Last edited by Scott; 04-08-2011 at 08:10 AM.. Reason: Please use code tags
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