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Shell Programming and Scripting

Replace prefix and suffix of a string

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# 1  
Old 01-14-2011
Replace prefix and suffix of a string
Hi, I'm new about shell scripting, and I need to do something like

abcd **1234** efgh

by

abcd '''1234''' efgh

I know that command sed helps about change one string by another, but I dont know how to keep whatever is inside **_** and replace * with '.

Thanks!
# 2  
Old 01-14-2011
Code:
echo "abcd **1234** efgh" | sed "s/*/'/g"

# 3  
Old 01-14-2011
Quote:
Originally Posted by anurag.singh
Code:
echo "abcd **1234** efgh" | sed "s/*/'/g"

I have tried this one but this change all the *, and I only want to change those strings who has two ** at the end and begginig. example:


**abcd **1234** efgh**
should be:
**abcd '''1234''' efgh**
# 4  
Old 01-14-2011
always post exact input (or most generalized one). Try following:
Code:
echo "**abcd **1234** efgh**" | sed "s/\*\*/'''/2;s/\*\*/'''/2"

OR
Code:
echo "**abcd **1234** efgh**" | sed "s/\*\*\([0-9]*\)\*\*/'''\1'''/"

This User Gave Thanks to anurag.singh For This Post:
selvaya
# 5  
Old 01-14-2011
Code:
 # echo "**abcd **1234** **efgh**" | ruby -e 's=gets.chomp.split(/\s+/);s.each{|x|x.gsub!(/\*\*(.*?)\*\*/,"\47\\1\47")};END{puts s.join(" ")}'
**abcd '1234' 'efgh'

# 6  
Old 01-17-2011
[QUOTE=anurag.singh;302488022]always post exact input (or most generalized one). Try following:
Code:
echo "**abcd **1234** efgh**" | sed "s/\*\*/'''/2;s/\*\*/'''/2"


Thanks! That's was exactly what I want Smilie
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