Shell Programming and Scripting

Thanks for reponse Scrutinizer.

!A[$0]++ if A[$0]=0 or "" then perform the default action, i.e. print $0. Afterwards increment the value of A[$0] (++)

Sorry to be a pain but how does( if A[$0]=0 or "") check for uniqueness and how does incrementing A[$0] (++) fit in.

From my understanding $0 is stored in an array,it than needs to be checked if the value already exist in the array if does not print it so i get lost at the the A[$0]++ part.is this adding it the unique value to the array which will later be checked again

Once again Sorry - Your code works perfectly I just need to get the hang arrays

Thanks


A[$0]++if A[$0]=0 or "" then perform the default action, i.e. print $0. Afterwards increment the value of A[$0] (++)

A[$0]++if A[$0]=0 or "" then perform the default action, i.e. print $0. Afterwards increment the value of A[$0] (++)

Hi, the first time $5 and $7 contain a combination of values array, for example BTS:34 and Cell:34A, then A[BTS:34 Cell:34A] does not contain a value, so the values get printed. Afterwards the value gets incremented, so A[BTS:34 Cell:34A] then contains the value 1. Each subsequent line where the $5 and $7 are present will not get printed (because it is not 0 or "") and the corresponding array value will be incremented.

Incrementing is just one thing, I could have done this too:


This would be another - less compact way - of accomplishing the same thing:

Code:

awk -F'[/"]' '{if(!A[$5,$7]){print $5,$7; A[$5,$7]=A[$5,$7]+1}}' infile

or

Code:

awk -F'[/"]' '{if(!A[$5,$7]){print $5,$7; A[$5,$7]=1}}' infile