For some reason, numero=`jobs | grep -n $trabajo | cut -d':' -f1`
that line wont save in numero the number I am looking for BUT if I write it in the bash...strangely, it works and saves the number.
What is wrong here? It's driving me crazy because if I type it manually it works flawless, however when executing the script it doesn't save the number in the variable.
Also, the echos are there just for testing purposes.
That is because jobs are local to the shell. When you run a script you are creating a child shell and in this child the list of jobs are not inherited from the parent.
Try sourcing your script-
$ . my_script.bash
This will run the script in the current shell where the jobs are defined.
Jobs will only list jobs started by the current shell. As your scipt is run in it's own version of the shell it won't should jobs started by the parent shell. You man need to use ps to do this (or run your script like bisbell describes above).
Also note that using -n on grep isn't very safe as your jobs might not be numbered from 1 (eg if you've run jobs in the past). best to use something like this:
or like this if you don't mind using the sed external:
Last edited by Chubler_XL; 12-21-2010 at 06:37 PM..
This User Gave Thanks to Chubler_XL For This Post:
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