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getopt invalid option selection

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# 1  
Old 12-20-2010
getopt invalid option selection
What is the significance of the *) and ?) in the below code.
Code:
while getopts a:b:c:he opt
do
   case $opt in
   a) _name="$OPTARG";;
   b) _project="$OPTARG";;
   c) line="$OPTARG";;
   e) _cmd="XX";;
   h) Projects=1;;
   *) echo "$OPTARG is an invalid option";
      my_exit 1;;
   ?) echo "$OPTARG is an invalid option";
      my_exit 1;;
   esac
done

As i believe the ?) will do the invalid option . What could be the value *) will take as per getopt command???

Thanks
posix
# 2  
Old 12-20-2010
In the case of getopts, no difference as ? matches one character, and * matches any number of characters.

Each option with getopts is only one character, so ? and * would both match an "invalid" option

However:
Code:
A=abc
case "$A" in
  ?) echo Question Mark;;
  *) echo Asterisk
esac

Output:
Asterisk

Code:
A=a
case "$A" in
  ?) echo Question Mark;;
  *) echo Asterisk
esac

Output: Question Mark

# 3  
Old 12-20-2010
An Introduction to the Unix Shell
R0H0N
# 4  
Old 12-20-2010
Not a big getopts fan since it limits you to only have one arguement
per character therefore I like using long argument names, which allows
you do something like this:

In addition, if you want you can add code in the *) section if you want
to print invalid options or ignore them. No need to worry about what ?
mark does.


Code:
 
while [ $# -gt 0 ]
do
 
case $1 in
         -+([bB]*(lock_count|LOCK_COUNT)))
          shift
          let block_count=$1
          ;;
         -+([lL]*(ist|IST)))
             let list=1
              ;;
        -+([hH]*(elp|ELP)))
            usage
            return 0;;
         *)
           shift ;;
esac
done

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