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# 1  
Old 12-10-2010
Find: return code check
Hi,

I've a find command like,

Code:
 
find /abcd/efgh -name "xxxx" 2> /dev/null > file1

what would be the condition to check if this returns none(means if the file "xxxx" is not present) ????

I tried checking with $? and it returns 72 to me but even the file is present also it returns the same 72.

Any suggestions ?

Thanks,
Vasanth
# 2  
Old 12-10-2010
Would the following suffice?
Code:
#!/bin/ksh
if [ -f xxxx ]
then
   echo "File exists"
else
   echo "File missing"
fi




I hope that this helps.


Robin
Liverpool/Blackburn
UK
# 3  
Old 12-10-2010
Code:
if [ -e "/abcd/efgh/xxxx" ] ; then
   echo "file exist"
else
   echo "file not exist"
fi


  • -e: Returns true value if file exists
  • -f: Return true value if file exists and regular file
R0H0N
# 4  
Old 12-10-2010
Thanks of your reply guys!

But, here I don't know the exact path. So i'm finding under /abcd/efgh instead of checking with if condition. It can be present in any of its sub directories. So now i need to check whether the find command is returning any directory list or not. Any suggestions?

Thanks,
Vasanth.
# 5  
Old 12-10-2010
Code:
if [ ! -z `find /abcd/efgh -name "xxxx" 2>/dev/null` ] ; then
    some files found
else
    no files
fi

This User Gave Thanks to For This Post:
skcvasanth
R0H0N
# 6  
Old 12-10-2010
If you run the "find" without redirecting the error channel, what error messages do you get? The error reply will be to do with that problem.

A "find" run should return zero whether or not it found the file. A value other than zero means that "find" encountered a problem during the search.
# 7  
Old 12-10-2010
Rohon,

That works great! Thanks a lot Smilie

Methyl,

I got few
Quote:
access related error
so i redirected them. Anyways now i was able to get the output as expected.

Thanks a lot guys for your reply!
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