How to get part of file?


 
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# 1  
Old 12-01-2010
How to get part of file?

Hi, Unix Gurus,
I have a file contains more than 60 columns, I want to get first 50 columns, how can I achive this? I don't want to use print $1, $2 ....

anybody has any idea?


Thanks in advance
ken002
# 2  
Old 12-01-2010
You could try
Code:
cut -f-50 file

. Use -d to specify the separation character. But it depends. Could you post a sample of your input file?
# 3  
Old 12-01-2010
Code:
awk 'NF=50' infile

This User Gave Thanks to rdcwayx For This Post:
# 4  
Old 12-01-2010
Quote:
Originally Posted by rdcwayx
Code:
awk 'NF=50' infile

Nice!
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